The alkyne which gives pyruvic acid $\left( {{\rm{C}}{{\rm{H}}_3}{\rm{COCOOH}}} \right)$ on oxidation with alk. ${\rm{KMn}}{{\rm{O}}_4}$ is:

${\rm{C}}{{\rm{H}}_3}{\rm{C}} \equiv {\rm{CH}}$

${\rm{C}}{{\rm{H}}_3}{\rm{C}} \equiv {\rm{C}}-{\rm{C}}{{\rm{H}}_3}$

${\rm{C}}{{\rm{H}}_3}-{\rm{C}}{{\rm{H}}_2}-{\rm{C}} \equiv {\rm{CH}}$

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JEE CHEMISTRY MCQ: HYDROCARBONS

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The alkyne which gives pyruvic acid

\left( {\mathrm{C}{\mathrm{H}_3}\mathrm{COCOOH}} \right)

on oxidation with alk.

\mathrm{KMn}{\mathrm{O}_4}

is:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_3}\mathrm{C} \equiv \mathrm{CH}

Option B (CH₃C≡CH) is correct because terminal alkynes with a methyl group adjacent to the triple bond yield pyruvic acid upon oxidation with alkaline KMnO₄.

JEE CHEMISTRY MCQ: HYDROCARBONS

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