NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Arrange the following complexes in correct order of crystal field splitting energy

\mathop {{{\left[ {Fe\left( {{H_2}{O_6}} \right)} \right]}^{2 + }}\,}\limits_I \,\,\,\,\,\mathop {\,{{\left[ {FeC{l_6}} \right]}^{ - 4}}}\limits_{II} \,\,\,\mathop {\,\,\,\,\,{{\left[ {Fe{{\left( {{H_2}O} \right)}_6}} \right]}^{3 + }}}\limits_{III}

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Correct option: A

III > I > II

Option A (III > I > II) is correct because the crystal field splitting energy depends on the charge of the metal ion and the strength of the ligand. Higher charge and stronger ligands lead to greater splitting.

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\left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;}

are example for isomerism The total number of stereoisomers for the complex

\left[\mathrm{Cr}(\mathrm{Ox})_{2} \mathrm{ClBr}\right]^{3-}

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\text{ox =}

oxalate) is The value of

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{\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]^x}

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\mathrm{M}{\mathrm{n}^{2 + }}

\mathrm{CuS}{\mathrm{O}_4}

decolourises on addition of KCN, the product is: The IUPAC name of

{\mathrm{K}_2}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right]