Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Medium
1 of 1
Application +4 | -1
If the integral
∫cos⁡8x+1cot⁡2x−tan⁡2xdx=Acos⁡8x+k\int \frac{\cos 8 x+1}{\cot 2 x-\tan 2 x} d x=A \cos 8 x+k
where kk is an arbitrary constant, then AA is equal to:
View answer and explanation
Correct option: A
−116-\frac{1}{16}
Option A (-1/16) is correct because the integral simplifies to a cosine function with a coefficient of -1/16.

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.