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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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The heat of combustion of ethanol determined by a bomb calorimeter is - 670.48 kcalmol−1mo{l^{ - 1}} at 250C{25^0}C.What is ∆U at 250C{25^0}C for the following reaction? C2H5OH(l)+72O2(g)→2CO2(g)+3H2O(g){\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}\left( l \right) + \frac{7}{2}{\mathrm{O}_2}\left( \mathrm{g} \right) \to 2\mathrm{C}{\mathrm{O}_2}\left( \mathrm{g} \right) + 3{\mathrm{H}_2}\mathrm{O}\left( \mathrm{g} \right)
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Correct option: C
−670.48kcal- 670.48\mathrm{kcal}
Option C (-670.48 kcal) is correct because at constant volume (bomb calorimeter), the heat of combustion is equal to the change in internal energy, ∆U.

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