JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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Understanding +4 | -1

If a point charge

\mathrm{q}

is placed at the centre of a cube what is the flux linked with the cube?

View answer and explanation

Correct option: A

\phi=\frac{1}{\epsilon_0} q

Option A (

\phi=\frac{1}{\epsilon_0} q

) is correct because Gauss's law states that the electric flux through a closed surface is equal to the enclosed charge divided by the permittivity of free space.

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