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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Application +4 | -1
The ion that has sp3d2s{p^3}{d^2} hybridisation for the central atom, is
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Correct option: C
[ICl4]−{[IC{l_4}]^ - }
Option C ([ICl4]−{[IC{l_4}]^ - }) is correct because its central iodine atom has 7 valence electrons, 4 bonded chlorine atoms, and a -1 charge, leading to sp3d2s{p^3}{d^2} hybridization.

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