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JEE MATHEMATICS MCQ: COMBINATIONS

1 Easy
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Application +4 | -1
The value of (21C1−10C1)+(21C2−10C2)+(21C3−10C3)+(21C4−10C4)+...+(21C10−10C10)\left( {{}^{21}{C_1} - {}^{10}{C_1}} \right) + \left( {{}^{21}{C_2} - {}^{10}{C_2}} \right) + \left( {{}^{21}{C_3} - {}^{10}{C_3}} \right) + \left( {{}^{21}{C_4} - {}^{10}{C_4}} \right) + ... + \left( {{}^{21}{C_{10}} - {}^{10}{C_{10}}} \right) is
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Correct option: D
220−210{2^{20}} - {2^{10}}
Option A (12/5) is correct because the variance is calculated using the formula npq for a binomial distribution.

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