If one root of the equation $i x^2-2(1+i) x+2-i=0$ is $(3-i)$, where $i=\sqrt{-1}$, the other root is

JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

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Application +4 | -1

If one root of the equation

i x^2-2(1+i) x+2-i=0

(3-i)

, where

i=\sqrt{-1}

, the other root is

View answer and explanation

Correct option: D

-1-i

Option D (-1-i) is correct because by using the sum of roots property for quadratic equations, the other root can be found.

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