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JEE MATHEMATICS MCQ: LIMITS

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lim⁡x→a{[(a1/2+x1/2a1/4−x1/4)−1−2(ax)1/4x3/4−a1/4x1/2+a1/2x1/4−a3/4]−1−2log⁡4a}8\lim \limits_{{x \rightarrow a}}\left\{\left[\left(\frac{a^{1 / 2}+x^{1 / 2}}{a^{1 / 4}-x^{1 / 4}}\right)^{-1}\right.\right.\left.-\frac{2(a x)^{1 / 4}}{x^{3 / 4}-a^{1 / 4} x^{1 / 2}+a^{1 / 2} x^{1 / 4}-a^{3 / 4}}\right]^{-1}\left.-\sqrt{2}^{\log_4a}\right\}^8 is equal to
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Correct option: C
a2a^2
Option C (a2) is correct because after simplifying the expression and substituting x=a, the limit evaluates to a2.

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