NEET UG PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

\mathrm{\vec A} + \mathrm{\vec B} = \mathrm{\vec C}\,and\,A = \sqrt 3 ,\,B = \sqrt 3 \,and\,C = 3

, then the angle between

\mathrm{\vec A}\;and\;\mathrm{\vec B}

View answer and explanation

Correct option: C

{60^0}

Option C (

{60^0}

) is correct because the angle is found using the law of cosines with the given magnitudes of the vectors.

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

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B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)