In the following reaction, the product ‘ $R$’ is $Ca{C_2}\xrightarrow{{{H_2}O}}P\xrightarrow[{{\rm{tube}}}]{{{\rm{Hot,}}\,{\rm{iron}}}}Q\xrightarrow{{C{H_3}Cl}}R$

NEET UG CHEMISTRY MCQ: HYDROCARBONS

1 Medium

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Application +4 | -1

In the following reaction, the product ‘

R

’ is

Ca{C_2}\xrightarrow{{{H_2}O}}P\xrightarrow[{\mathrm{tube}}]{{\mathrm{Hot,}\,\mathrm{iron}}}Q\xrightarrow{{C{H_3}Cl}}R

View answer and explanation

Correct option: C

toluene

Benzoic acid is the correct answer because toluene (formed by Friedel-Crafts alkylation of benzene) is oxidized by

KMn{O_4}

to form benzoic acid.