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JEE CHEMISTRY MCQ: BIOMOLECULES

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Fehling’s solution and benedict’s solution are reduced by glucose to form:
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Correct option: B
Cu2O\mathrm{C}{\mathrm{u}_2}\mathrm{O}
Option B (Cu2O\mathrm{C}{\mathrm{u}_2}\mathrm{O}) is correct because glucose reduces Cu²⁺ ions in Fehling's and Benedict's solutions to Cu⁺, forming cuprous oxide (Cu2O\mathrm{C}{\mathrm{u}_2}\mathrm{O}), which is a red precipitate.

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