JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

The set of values of

x

satisfying

x^2-x-\pi+\sin ^{-1}(\sin 2)<0

, is

View answer and explanation

Correct option: C

(-1,2)

Option C ((-1,2)) is correct because simplifying the inequality

x^2 - x - \pi + \sin^{-1}(\sin 2) < 0

leads to the solution set (-1, 2).

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