JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

f(x)=A \sin \frac{\pi x}{2}+B, f^{\prime}(1 / 2)=\sqrt{2}

and

\int\limits_{0}^1 f(x) \mathrm{d} x=\frac{2 A}{\pi}

then the constants

A

and

B

are respectively

View answer and explanation

Correct option: D

4 / \pi, 0

Option D (4/

\pi

, 0) is correct because solving the given equations for A and B yields these values.

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