JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

The energy of an electron in the ground state

(n=1)

for

{He}^{+}

ion is

-x \mathrm{~J},

then that for an electron in

n=2

state for

{Be}^{3+}

ion in

\mathrm{J}

View answer and explanation

Correct option: D

-x

Option A (

\mathrm{A}=10^{15}

and

\mathrm{E}_{\mathrm{a}}=1.9 \times 10^4 \mathrm{~KJ}

) is correct because it is obtained by comparing the given equation with the Arrhenius equation in logarithmic form.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.