Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
1 of 1
Application +4 | -1
If f  (x)=  {1−x,0,(2−x)2,  0≤   x  ≤11≤   x  ≤22≤   x  ≤3f\,\,\left( x \right) = \,\,\left\{ {\begin{array}{cccccccccccccccccccc} {1 - x,}\\ {0,}\\ {{{\left( {2 - x} \right)}^2},} \end{array}\,\,\begin{array}{cccccccccccccccccccc} {0 \le \,\,\,x\,\, \le 1}\\ {1 \le \,\,\,x\,\, \le 2}\\ {2 \le \,\,\,x\,\, \le 3} \end{array}} \right. and ϕ  (x)=∫0x  f (t)  dt\phi \,\,\left( x \right) = \int \limits_0^x \,\,f\,\left( t \right)\,\,dt. Then, for any x∈[2,3],  ϕ  (x)x \in \left[ {2,3} \right],\,\,\phi \,\,\left( x \right) equals

View answer and explanation
Correct option: C
12  +  (x−2)33\frac{1}{2}\,\, + \,\,\frac{{{{\left( {x - 2} \right)}^3}}}{3}
Option C is correct because the integral of f(t) from 0 to x is calculated piecewise, resulting in the given expression for x in [2,3].

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.