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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let {an}n=0∞\left\{a_n\right\}_{n=0}^{\infty} be a sequence such that a0=a1=0a_0=a_1=0 and an+2=3an+1−2an+1,∀n≥0a_{n+2}=3 a_{n+1}-2 a_n+1, \forall n \geq 0
Then a25 a23−2a25 a22−2a23 a24+4a22 a24a_{25}\, a_{23}-2 a_{25}\, a_{22}-2 a_{23}\, a_{24}+4 a_{22}\, a_{24} is equal to
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Correct option: B
528
Option B (528) is correct because by recursively applying the given sequence relation and simplifying the expression, the result is 528.

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