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JEE MATHEMATICS MCQ: PARABOLA

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Analyzing +4 | -1
If y=m1x+c1y = {m_1}x + {c_1} and y=m2x+c2,  m1≠m2y = {m_2}x + {c_2},\,\,{m_1} \ne {m_2} are two common tangents of circle x2+y2=2{x^2} + {y^2} = 2 and parabola y2=x,{y^2} = x, then the value of 8∣m1m2∣8\left| {{m_1}{m_2}} \right| is equal to
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Correct option: C
−4+32- 4 + 3\sqrt 2
The correct answer is C (−4+32- 4 + 3\sqrt 2) because it is the value of 8∣m1m2∣8|m_1m_2| calculated using the condition for common tangents to the circle and parabola.

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