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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If ∫02(2x−2x−x2)dx=∫01(1−1−y2−y22)dy+\int_0^2\left(\sqrt{2 x}-\sqrt{2 x-x^2}\right) d x=\int_0^1\left(1-\sqrt{1-y^2}-\frac{y^2}{2}\right) d y+ ∫12(2−y22)dy+I\int_1^2\left(2-\frac{y^2}{2}\right) d y+I then II equal is
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Correct option: C
∫01(1−1−y2)dy\int_0^1\left(1-\sqrt{1-y^2}\right) d y
Option C (∫01(1−1−y2)dy\int_0^1\left(1-\sqrt{1-y^2}\right) d y) is the correct answer because it results from simplifying and rearranging the given integral equation.

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