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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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The value of ∫−13  [tan⁡−1  (xx2+  1)  +  tan⁡−1  (x2+1x)]    dx\int \nolimits_{ - 1}^3 \,\,\left[ {{{\tan }^{ - 1}}\,\,\left( {\frac{x}{{{x^2} + \,\,1}}} \right)\,\, + \,\,{{\tan }^{ - 1}}\,\,\left( {\frac{{{x^2} + 1}}{x}} \right)} \right]\;\,\,dx is
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Correct option: A
2 π2\,\mathrm{\pi }
Option A (2π2\pi) is correct because the expression inside the integral simplifies to π/2\pi/2, and the integral of a constant is straightforward.

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