JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

f(x)=\int_0^{\sin x} \cos ^{-1} t d t+\int_0^{\cos x} \sin ^{-1} t d t

0 < x < \frac{\pi }{2}

, then

f(\pi / 4)

is equal to

View answer and explanation

Correct option: B

1+\frac{\pi}{2 \sqrt{2}}

Option C (

-\frac{1}{2}

) is correct because it is the value of the function f(x) after differentiating the given integral equation and substituting

x = \frac{\pi}{6}

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