NEET UG CHEMISTRY MCQ: S-BLOCK ELEMENTS

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Analyzing +4 | -1

Which pair cannot exist together in solution?

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Correct option: C

\mathrm{NaHC}{\mathrm{O}_3}\mathrm{and N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}

Option A (

\mathrm{NaHC}{\mathrm{O}_3}\mathrm{and NaOH}

) is correct because

\mathrm{NaHC}{\mathrm{O}_3}

reacts with

\mathrm{NaOH}

to form

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}

and

{\mathrm{H}_2}\mathrm{O}

, hence they cannot coexist.

More Questions from S-BLOCK ELEMENTS

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\mathrm{BaCl}_{2}

\mathrm{Na}_{3} \mathrm{PO}_{4}

\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}

\underset {\text{(dilute)}}{Ba(OH)_2}+H_2O_2+ClO_2 \longrightarrow