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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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11⋅2⋅3⋅4+43⋅4⋅5⋅6+95⋅6⋅7⋅8+167⋅8⋅9⋅10+…to  ∞\frac{1}{{1 \cdot 2 \cdot 3 \cdot 4}} + \frac{4}{{3 \cdot 4 \cdot 5 \cdot 6}} + \frac{9}{{5 \cdot 6 \cdot 7 \cdot 8}} + \frac{{16}}{{7 \cdot 8 \cdot 9 \cdot 10}} + \ldots \mathrm{to\;}\infty is equal to
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Correct option: A
16log⁡e2−124\frac{1}{6}{\log _e}2 - \frac{1}{{24}}
Option A (16log⁡e2−124\frac{1}{6}{\log _e}2 - \frac{1}{{24}}) is correct because the infinite series simplifies to 16log⁡e2−124\frac{1}{6}{\log _e}2 - \frac{1}{{24}}.

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