The coefficient of linear expansion of brass and steel are ${\alpha _1}$ and ${\alpha _2}$. If we take a brass rod of length ${l_1}$ and steel rod of length ${l_2}$ at ${0^0}C$, their difference in length $\left( {{l_2} - {l_1}} \right)$ will remain the same at a temperature if

${\alpha _1}{l_2} = {\alpha _2}{l_1}$

${\alpha _1}l_2^2 = {\alpha _2}l_1^2$

$\alpha _1^2{l_1} = \alpha _2^2{l_2}$

JEE PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

1 Medium

1 of 1

Application +4 | -1

The coefficient of linear expansion of brass and steel are

{\alpha _1}

and

{\alpha _2}

. If we take a brass rod of length

{l_1}

and steel rod of length

{l_2}

{0^0}C

, their difference in length

\left( {{l_2} - {l_1}} \right)

will remain the same at a temperature if

View answer and explanation

Correct option: D

{\alpha _1}{l_1} = {\alpha _2}{l_2}

Option D (

{\alpha _1}{l_1} = {\alpha _2}{l_2}

) is correct because for the difference in length to remain the same, the change in length of both rods must be equal.