If $-1+\sqrt{-3}=r e^{i \theta}$, then the value of $\theta$ is

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

-1+\sqrt{-3}=r e^{i \theta}

, then the value of

\theta

View answer and explanation

Correct option: A

2 \pi / 3

Option A (

2 \pi / 3

) is correct because the complex number lies in the second quadrant, and the argument is calculated accordingly.

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{\left| {1 - i} \right|^x} = {2^x}

|z|=1

z \neq \pm 1

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

{\left( {1 - {x^2} + x} \right)^6} - {\left( {1 - x + {x^2}} \right)^6}