${O^{2 - }}$ and $S{i^{4 + }}$ are iso electronic ions. If the ionic radius of ${O^{2 - }}$ is $1\,\,\mathop {\rm{A}}\limits^{\rm{o}} $, the ionic radius of $S{i^{4 + }}$ is

$0.41\,\mathop {\rm{A}}\limits^{\rm{o}} $

$1\,.4\,\mathop {\rm{A}}\limits^{\rm{o}} $

$2.8\mathop {\rm{A}}\limits^{\rm{o}} $

$1.5\mathop {\rm{A}}\limits^{\rm{o}} $

NEET UG CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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{O^{2 - }}

and

S{i^{4 + }}

are iso electronic ions. If the ionic radius of

{O^{2 - }}

1\,\,\mathop \mathrm{A}\limits^\mathrm{o}

, the ionic radius of

S{i^{4 + }}

View answer and explanation

Correct option: B

0.41\,\mathop \mathrm{A}\limits^\mathrm{o}

Option A (

M{g^{2 + }}

) is correct because

M{g^{2 + }}

has a higher nuclear charge and fewer electrons than Ne, resulting in a smaller ionic radius.