JEE PHYSICS MCQ: WAVE OPTICS

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A Young's double slit apparatus has slits separated by

0.28 \mathrm{~mm}

and a screen

48 \mathrm{~cm}

away from the slits. The whole apparatus is immersed in water and the slits are illuminated by the red light (

\lambda=700 \mathrm{~nm}

in vacuum). Find the fringe-width of the pattern formed on the screen.

View answer and explanation

Correct option: A

0.90 mm

Option A (0.90 mm) is correct because it is calculated using the formula for fringe width in Young's double-slit experiment, considering the refractive index of water.

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