JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Analyzing +4 | -1

\alpha-\beta=

constant, then the locus of the point of intersection of tangents at

P(a \cos \alpha, b \sin \alpha)

and

Q(a \cos \beta, b \sin \beta)

to the ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

, is

View answer and explanation

Correct option: C

An ellipse

Option C (An ellipse) is correct because the locus of the point of intersection of tangents at P and Q to the ellipse is another ellipse.

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S

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\frac{x^2}{25}+\frac{y^2}{16}=1

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Q

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N P

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P

O