If ${\sin ^2}\,\,{\rm{\theta }} = \frac{1}{4}$ , then the most general value of ${\rm{\theta }}$ is

$n{\rm{\pi }}\,\, \pm \,\,\frac{{\rm{\pi }}}{6}$

$2\,n{\rm{\pi }}\,\, \pm \,\,{\left( { - 1} \right)^n}\,\,\frac{{\rm{\pi }}}{6}$

$\frac{{n{\rm{\pi }}}}{2}\,\, \pm \,\,{\left( { - 1} \right)^n}\,\,\frac{{\rm{\pi }}}{6}$

$2\,n{\rm{\pi }}\,\, \pm \,\,\frac{{\rm{\pi }}}{6}$

JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

{\sin ^2}\,\,\mathrm{\theta } = \frac{1}{4}

, then the most general value of

\mathrm{\theta }

View answer and explanation

Correct option: C

n\mathrm{\pi }\,\, \pm \,\,\frac{\mathrm{\pi }}{6}

Option C (

n\mathrm{\pi }\\; \pm \\; {\rm{\frac{{\pi }}{6}}}

) is correct because it represents the general solution for the given trigonometric equation.

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