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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
The equation of a transverse wave on a stretched string is given by y=0.05sin⁡2π(t0.002−x0.1)y=0.05 \sin 2 \pi\left(\frac{t}{0.002}-\frac{x}{0.1}\right), where xx and yy are expressed in metre and tt in second. The speed of the wave is
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Correct option: B
50 ms−150 \mathrm{~ms}^{-1}
Option B (50 ms−150 \mathrm{~ms}^{-1}) is correct because the speed of the wave is the ratio of the coefficient of t to the coefficient of x in the wave equation.

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