JEE PHYSICS MCQ: MAGNETIC EFFECT OF CURRENT

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Application +4 | -1

A circular coil of 200 turns has a radius of

10 \mathrm{~cm}

and carries a current of

2.0 \mathrm{~A}

. (a) Find the magnitude of the magnetic field

\vec{B}

at the centre of the coil. (b) At what distance from the centre along the axis of the coil will the field

B

drop to half its value at the centre?

(\sqrt[3]{4}=1.5874 \ldots)

View answer and explanation

Correct option: A

2.512 mT; 7.66 cm

Option A (2.512 mT; 7.66 cm) is correct because it accurately calculates the magnetic field at the center of the coil and the distance at which the field drops to half its value.

More Questions from MAGNETIC EFFECT OF CURRENT

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A needle made of bismuth is suspended freely in a magnetic field. The angle which the needle makes with the magnetic field is: Assertion: If a charged particles is moving in perpendicular uniform magnetic field, its kinetic energy does not change
Reason: Velocity of charge particle is not changing in magnetic field. Pick out the wrong statement : A steady current is flowing in a circular coil of radius

R

, made up of a thin conducting wire. The magnetic field at the center of the loop is

B_L

. Now, a circular loop of radius

R/n

is made from the same wire without changing its length, by unfolding and refolding the loop, and the same current is passed through it. If new magnetic field at the center of the coil is

B_C

, then the ratio

B_L / B_C

is Lorentz force can be calculated by using the formula Two particles

X

and

Y

having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular path of radius

R_1

and

R_2

respectively. The ratio of mass of

{X}

to that of

{Y}

is :