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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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Application +4 | -1
If a2−2acos⁡x+1=674a^2-2 a \cos x+1=674 and tan⁡(x/2)=7\tan (x / 2)=7 then the integral value of aa is
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Correct option: A
25
Option A (25) is correct because solving the equation a2−2acos⁡x+1=674a^2-2 a \cos x+1=674 with tan⁡(x/2)=7\tan (x / 2)=7 yields a=25a=25.

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