The value of $\frac{{{{\cot }^2}\,\,{\rm{\theta }} + 1}}{{{{\cot }^2}\,\,{\rm{\theta }} - 1}}$ is equal to

${\rm{cosec}}\;\,\,2{\rm{\theta }}$

JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

The value of

\frac{{{{\cot }^2}\,\,\mathrm{\theta } + 1}}{{{{\cot }^2}\,\,\mathrm{\theta } - 1}}

is equal to

View answer and explanation

Correct option: D

\sec \,\,2\mathrm{\theta }

Option D (

\sec \,2\mathrm{\theta }

) is correct because the given expression can be simplified using trigonometric identities to equal

\sec \,2\mathrm{\theta }

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