JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

\log _3 2, \log _3\left(2^x-5\right)

and

\log _3\left(2^x-\frac{7}{2}\right)

are in A.P. then

x=k

. Then

2 {k}

is equal to

View answer and explanation

Correct option: A

Option A (6) is correct because solving the arithmetic progression condition for the given logarithms leads to x=3, and 2k = 2*3 = 6.

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