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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If for a continuous function ff, ∫−aaf(x)dx=K∫0a(f(x)+f(−x))dx\int\limits_{{-a}}^a f(x) d x=K \int\limits_{0}^a(f(x)+f(-x)) d x then the value of KK is
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Correct option: A
1
Option A (1) is correct because ∫−aaf(x)dx=∫0a(f(x)+f(−x))dx\int_{-a}^{a} f(x) dx = \int_{0}^{a} (f(x) + f(-x)) dx, so K=1K=1.

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