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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

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Application +4 | -1

The number of ways in which ten candidates

A_1, A_2, A_3, A_4, \cdots, A_{10}

can be arranged in a row "If

A_1

is always above

A_2

is

View answer and explanation

Correct option: B

\frac{10 !}{2 !}

Option B (

\frac{{10 !}}{{2 !}}

) is correct because it considers all possible arrangements of the 10 candidates and then divides by 2! to account for the fact that

A_1

must always be above

A_2

.

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