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JEE CHEMISTRY MCQ: HYDROGEN

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The recommended concentration of fluoride ion in drinking water is up to 1 ppm as fluoride ion is required to make teeth enamel harder by converting [3Ca3(PO4)2⋅Ca(OH)2] \left[ {3C{a_3}{{\left( {P{O_4}} \right)}_2} \cdot Ca{{\left( {OH} \right)}_2}} \right]\, to:
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Correct option: C
[3Ca3(PO4)2⋅CaF2]\left[ {3C{a_3}{{\left( {P{O_4}} \right)}_2} \cdot Ca{F_2}} \right]
Option D is correct because fluoride ions convert hydroxyapatite to fluorapatite, which is represented by the formula [3{Ca3(PO4)2}⋅CaF2]\left[ {3\{C{a_3}{{\left( {P{O_4}} \right)}_2}\} \cdot Ca{F_2}} \right].

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