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JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1
If fβ€²(a)=2f'\left( a \right) = 2 and f(a)=4f\left( a \right) = 4, then lim⁑xβ†’axf(a)βˆ’af(x)xβˆ’a\lim\limits_{x \to a} \frac{{xf\left( a \right) - af\left( x \right)}}{{x - a}} equals
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Correct option: B
4βˆ’2a4 - 2a
Option B (4 - 2a) is correct because it is the result of applying L'Hopital's rule or algebraic manipulation to the limit expression.

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