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JEE MATHEMATICS MCQ: RATE MEASURE

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A cone whose height is always equal to its diameter is increasing in volume at the rate of

40 \mathrm{~cm}^3 / \mathrm{sec}

. At what rate is the radius increasing when its circular base area is

1 \mathrm{~m}^2

?

View answer and explanation

Correct option: D

0.002 \mathrm{~cm} / \mathrm{sec}

The correct answer is D (

0.002 \mathrm{~cm} / \mathrm{sec}

) because it is the rate of change of the radius calculated using related rates and the given volume increase.

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