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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
If ∫sin⁡θcos⁡θf(xtan⁡θ)dx(θ≠nπ2,n∈I)\int_{\sin \theta}^{\cos \theta} f(x \tan \theta) d x\left(\theta \neq \frac{n \pi}{2}, n \in I\right) is equal to
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Correct option: A
−cos⁡θ∫1tan⁡θf(xsin⁡θ)dx-\cos \theta \int_1^{\tan \theta} f(x \sin \theta) d x
Option A is correct because by substituting xtan⁡θ=zsin⁡θx \tan \theta = z \sin \theta and changing the limits of integration, the integral can be simplified to the form given in option A.

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