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NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

1 Easy
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Application +4 | -1
An elevator car whose floor to ceiling distance is 2.7 m2.7 \mathrm{~m} starts ascending with a constant acceleration of 1.2 ms−2.2 s1.2 \mathrm{~ms}^{-2} .2 \mathrm{~s} after the start, a bolt falls from the ceiling of the car. The free fall time of the bolt is (Take, g=9.8 ms−2g=9.8 \mathrm{~ms}^{-2} )
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Correct option: D
5.411 s\sqrt{\frac{5.4}{11}} \mathrm{~s}
Option D (5.411 s\sqrt{\frac{5.4}{11}} \mathrm{~s}) is correct because it accounts for the initial upward velocity of the bolt due to the elevator's acceleration and the additional distance covered during the fall.

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