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JEE MATHEMATICS MCQ: BINOMIAL THEOREM

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sin⁡nx=∑r=0narsin⁡rx\sin n x=\sum\limits_{{r=0}}^n a_r \sin ^r x, where nn is an odd natural number. Then
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Correct option: C
a0=0,a1=na_0=0, a_1=n
Option C (a0=0,a1=na_0=0, a_1=n) is correct because by expanding sin⁡nx\sin nx using the imaginary part of Euler's formula, the constant term is zero and the coefficient of sin⁡x\sin x is nn.

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