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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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A carnot engine operates between temperature T and 400 K (T>400 K). If efficiency of engine is 25%, the temperature T is:
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Correct option: C
533.3 K
Option C (533.3 K) is correct because the efficiency of a Carnot engine is given by η=1−TcTh\eta = 1 - \frac{T_c}{T_h}, where TcT_c is the cold reservoir temperature and ThT_h is the hot reservoir temperature. Solving for ThT_h with the given efficiency yields approximately 533.3 K.

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