If $f(x)=x^3+b x^2+c x+d$ and $0 < b^2 < c$, then in $(-\infty, \infty)$

$f(x)$ is a strictly decreasing function

JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

1 of 1

Analyzing +4 | -1

f(x)=x^3+b x^2+c x+d

and

0 < b^2 < c

, then in

(-\infty, \infty)

View answer and explanation

Correct option: A

f(x)

is strictly increasing function

The correct answer is A (

f(x)

is strictly increasing function) because the derivative

f'(x)

is always positive, indicating that

f(x)

is strictly increasing.

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)