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JEE MATHEMATICS MCQ: ELLIPSE

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The sum of focal distance of any point on the ellipse with major and minor axes as 2a2a and 2b2b respectively, is equal to
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Correct option: A
2a2a
Option A (2a2a) is correct because the sum of the focal distances of any point on the ellipse is equal to the length of the major axis, which is 2a.

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Let x2144+y281=1\frac{x^2}{144}+\frac{y^2}{81}=1 be the equation of an ellipse. If mm be the minimum value of the segment of tangent to the ellipse intercepted by the coordinate axes and M\mathrm{M} be the maximum distance of the centre of the ellipse from the normal, then the value of mM\mathrm{mM} is equal to Let PP be a variable point on the ellipse x225+y216=1\frac{{{x^2}}}{{25}} + \frac{{{y^2}}}{{16}} = 1 with foci at SS and S′.S'. If AA be the area of triangle PSS′,PSS', then the maximum value of AA is If the co-ordinates of two points AA and BB are (7,0)(\sqrt{7}, 0) and (−7,0)(-\sqrt{7}, 0) respectively and PP is any point on the conic, 9x2+16y2=1449 x^{2}+16 y^{2}=144, then PA+PB\mathrm{PA}+\mathrm{PB} is equal to :
The slope of a common tangent to the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 and a concentric circle of radius rr, is A tangent to the ellipse x225+y216=1\frac{x^2}{25}+\frac{y^2}{16}=1 at any point PP meet the line x=0x=0 at a point QQ. Let RR be the image of QQ in the line y=xy=x, then circle whose extremities of a diameter are QQ and RR passes through a fixed point. The fixed point is Any ordinate NPN P of an ellipse meets the auxiliary circle at QQ. Then, the locus of the intersection of the normal at PP and OO is the circle
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