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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
If chords of contact of the tangent from two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) to the ellipse x2a2+y2b2=1\frac{x^2}{a^2}+\frac{y^2}{b^2}=1 are at right angles, then x1x2a2×y1y2b2\frac{x_1x_2}{a^2} \times \frac{y_1y_2}{b^2} is equal to
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Correct option: C
−a4b4\frac{-a^4}{b^4}
Option C (−a4b4\frac{{-a^4}}{{b^4}}) is correct because the product of the slopes of the chords of contact must equal -1 due to their perpendicularity.

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