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JEE PHYSICS MCQ: WAVES

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Application +4 | -1
A transverse wave described by
y=(0.02 m)sin⁡[(1.0 m−1)x+(30 s−1)t]y=(0.02 \mathrm{~m}) \sin \left[\left(1.0 \mathrm{~m}^{-1}\right) x+\left(30 \mathrm{~s}^{-1}\right) t\right] propagates on a stretched string having a linear mass density of 1.2×10−4 kg m−11.2 \times 10^{-4} \mathrm{~kg} \mathrm{~m}^{-1}. Find the tension in the string.
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Correct option: A
0.108 N
Option A (0.108 N) is correct because it is calculated using the wave equation and the linear mass density to find the tension in the string.

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