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NEET UG PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1
Calculate change in internal energy of a system which has absorbed 2 kcal of heat and done 500 J of work
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Correct option: A
7900 J
Option B (8900 J) is correct because it is the change in internal energy calculated using the first law of thermodynamics: ΔU=Q−W\Delta U = Q - W.

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