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JEE MATHEMATICS MCQ: COMPOUND ANGLES

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If

\tan (\alpha-\beta)=\frac{\sin (2 \beta)}{3-\cos (2 \beta)}

, then

\tan \alpha=f(\beta)

. The value of

f\left(\frac{\pi}{3}\right)

equals:

View answer and explanation

Correct option: C

2 \sqrt{3}

Option C is correct because substituting

\beta = \frac{{\pi}}{{3}}

and simplifying leads to

\tan \alpha = 2\sqrt{{3}}

.

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\tan \left( {A + B} \right) = p

\tan \left( {A - B} \right) = q

, then the value of

\tan \,\,2A

is The value of

\cos \,\,x\,\,\cos \,\,y\,\,\sin \,\,\left( {x - y} \right) + \cos \,\,y\,\,\cos \,\,z\,\,\sin \,\,\left( {y - z} \right)

+ \cos \,\,z\,\,\cos \,\,x\,\,\sin \,\,\left( {z - x} \right) + \sin \,\,\left( {x - y} \right)\sin \,\,\left( {y - z} \right)\,\,\sin \,\,\left( {z - x} \right)

, is
The sides of a triangle are

\sin \alpha, \cos \alpha

\sqrt{1+\sin \alpha \cos \alpha}

0<\alpha<\frac{\pi}{2}

. Then, the greatest angle of the triangle is If

\tan \,\,A = 2\,\,\tan \,\,B + \cot \,\,B,\;\;\mathrm{then}\;\,2\,\,\tan \left( {A - B} \right)\mathrm{\;}

is equal to

If

A,B,C

are angles of a triangle, then the minimum value of

{\tan ^2}\,\,\frac{A}{2} + {\tan ^2}\,\,\frac{B}{2} + {\tan ^2}\,\,\frac{C}{2}

A > 0,\,\;B > 0

A + B = \frac{\pi }{3}

, then the maximum value of

\tan A\,\,\tan B