JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1

A copper wire of length 10 m and radius

({10^{ - 2}}/\sqrt \pi )\,\mathrm{m}

has electrical resistance of

10\,\Omega

. The current density in the wire for an electric field strength of 10 (V/m) is:

View answer and explanation

Correct option: A

{10^5}\,\mathrm{A/}{\mathrm{m}^2}

Option A (

{10^5}\,\mathrm{A/}{\mathrm{m}^2}

) is correct because it is calculated using the formula relating current density, electric field, and conductivity.

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